document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019419>Question 1019419</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bag contains eight chips numbered 1 through 8. Two chips are drawn randomly from the bag and laid down in the order they were drawn. What is the probability that the 2-digit number formed is divisible by 3? Convert to a percent and round to the tenths place.\r<BR>\n" );
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document.write( "I need help because I don't understand and my teacher didn't explain this clear enough to me </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635372 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635372\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We are looking for all(there is no 0 or 9) the two-digit numbers between 12 and 87 which are divisible by 3, they are<BR>\n" );
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document.write( "12, 15, 18, 21, 24, 27, 36, 42, 45, 48, 51, 54, 57, 63, 72, 75, 78, 81, 84, 87<BR>\n" );
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document.write( ": A number is divisible by 3 if the sum of its digits is divisible by 3<BR>\n" );
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document.write( "There are 20 numbers divisible by 3 out of 8 * 7 = 56 possibilities <BR>\n" );
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document.write( "The probability(Pr) of a two digit number divisible by 3 is 20 / 56 = 0.357142857<BR>\n" );
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document.write( "Pr = 35.714 = 35.7%<BR>\n" );
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