document.write( "Question 87631: Solve by completing the square\r
\n" ); document.write( "\n" ); document.write( "x^2+4x-3=0 \n" ); document.write( "
Algebra.Com's Answer #63535 by SandySharma(35)\"\" \"About 
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\"x%5E2%2B4x-3=0+\"\r
\n" ); document.write( "\n" ); document.write( "Add 7 on both sides, we will get\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x-3+%2B+7+=7+\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2%2B4x%2B4=7\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2B2%29%5E2=7\"\r
\n" ); document.write( "\n" ); document.write( "Take square root on both sides, we will get\r
\n" ); document.write( "\n" ); document.write( "\"x%2B2=+sqrt%287%29\"\r
\n" ); document.write( "\n" ); document.write( "x + 2 = +2.65
\n" ); document.write( "or
\n" ); document.write( "x + 2 = -2.65\r
\n" ); document.write( "\n" ); document.write( "x = 0.65, -4.65\r
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