document.write( "Question 1019301: In a quadratic variation graph what does it look like when y equals 18 when x equals 6 what does the rest of the graph look like. \n" ); document.write( "
Algebra.Com's Answer #635338 by Theo(13342)\"\" \"About 
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you did not specify whether this was direct or inverse variation.\r
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\n" ); document.write( "\n" ); document.write( "the formula for direct variation would be y = kx^2.\r
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\n" ); document.write( "\n" ); document.write( "the formula for inverse variation would be y = k/x^2.\r
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\n" ); document.write( "\n" ); document.write( "in both cases, you solve for k first and then use that value of k to solve the rest of the problem.\r
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\n" ); document.write( "\n" ); document.write( "you are given that y = 18 when x equals 6.\r
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\n" ); document.write( "\n" ); document.write( "in direct variation the formula of y = kx^2 becomes 18 = k*6^2 which becomes 18 = 36k.\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get k = 18/36 = .5\r
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\n" ); document.write( "\n" ); document.write( "now that you have k, you can make the graph.\r
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\n" ); document.write( "\n" ); document.write( "it will look like the following:\r
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\n" ); document.write( "\n" ); document.write( "in inverse variation, the formula of y = k/x^2 becomes 18 = k/6^2 which becomes 18 = k/36.\r
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\n" ); document.write( "\n" ); document.write( "solve for k to get k = 18*36 = 648.\r
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\n" ); document.write( "\n" ); document.write( "now that you have k, you can make the graph.\r
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\n" ); document.write( "\n" ); document.write( "it will look like the following:\r
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