document.write( "Question 1019325: the medians of a right triangle that are drawn from the vertices of the acute angles have lengths of 2 square root 13 and square root 73. find the lengths of the hypotenuse. \n" ); document.write( "
Algebra.Com's Answer #635326 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "The medians of a right triangle that are drawn from the vertices of the acute angles have lengths of 2 square root 13 and square root 73. Find the lengths of the hypotenuse.
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\n" ); document.write( "\n" ); document.write( "Answer. The length of the hypotenuse is 10 units.\r
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document.write( "Solution\r\n" );
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document.write( "We will use this property of a median, which is valid for any triangle:\r\n" );
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document.write( "  In a triangle with the sides a, b and c, the median drawn to the side c has the length \"m%5Bc%5D\" = \"sqrt%28%282a%5E2+%2B+2b%5E2+-+c%5E2%29%2F2%29\".\r\n" );
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document.write( "See the lesson The length of a median of a triangle in this site.\r\n" );
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document.write( "Next, let us apply the property to a right-angled triangle, whose legs are a and b units long and the hypotenuse is c units long.\r\n" );
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document.write( "For the medians  \"m%5Ba%5D\"  and  \"m%5Bb%5D\"  drawn to the legs a and b respectively, we will have\r\n" );
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document.write( "\"m%5Ba%5D%5E2\" = \"%282b%5E2+%2B+2c%5E2+-+a%5E2%29%2F4\",  \"m%5Bb%5D%5E2\" = \"%282a%5E2+%2B+2c%5E2+-+b%5E2%29%2F4\". \r\n" );
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document.write( "Therefore,\r\n" );
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document.write( "\"m%5Ba%5D%5E2\" + \"m%5Bb%5D%5E2\" = \"%282b%5E2+%2B+2c%5E2+-+a%5E2%29%2F4\" + \"%282a%5E2+%2B+2c%5E2+-+b%5E2%29%2F4\" = \"%282b%5E2+%2B+2c%5E2+-+a%5E2+%2B+2a%5E2+%2B+2c%5E2+-+b%5E2%29%2F4\" = \"%28a%5E2+%2B+b%5E2+%2B+4c%5E2%29%2F4\".\r\n" );
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document.write( "Since for the right-angled triangle \"a%5E2+%2B+b%5E2\" = \"c%5E2\", you can rewrite the above equality in the form\r\n" );
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document.write( "\"m%5Ba%5D%5E2\" + \"m%5Bb%5D%5E2\" = \"%28c%5E2+%2B+4c%5E2%29%2F4\" = \"%285%2F4%29%2Ac%5E2\".\r\n" );
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document.write( "Now substitute the given data  \"m%5Ba%5D\" = \"2%2Asqrt%2813%29\"  and  \"m%5Bb%5D\" = \"sqrt%2873%29\". You will get\r\n" );
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document.write( "\"%285%2F4%29c%5E2\" = \"4%2A13+%2B+73\" = \"125\".\r\n" );
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document.write( "It implies  \"c%5E2\" = \"%284%2F5%29%2A125\" = \"100\".\r\n" );
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document.write( "Hence, c = 10.\r\n" );
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document.write( "The problem is solved.\r\n" );
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