document.write( "Question 1019370: An executive flew in the corporate jet to a meeting in a city 1500 kilometers away. After traveling the same amount of time on the return flight, the pilot mentioned that they still had 300 kilometers to go. The air speed of the plane was 600 kilometers per hour. How fast was the wind blowing? (Assume that the wind direction was parallel to the flight path and constant all day. Round your answer to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #635290 by robertb(5830)\"\" \"About 
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Let r = wind speed.\r
\n" ); document.write( "\n" ); document.write( "In the outbound flight of the plane, its net speed will be 600 + r, while in the return trip it would be 600 - r. (The plane would be flying parallel AGAINST the wind.)\r
\n" ); document.write( "\n" ); document.write( "In the outbound flight, using the formula d = r*t, the time duration of flight is \"1500%2F%28600%2Br%29\" hours.\r
\n" ); document.write( "\n" ); document.write( "In the return flight, after travelling \"1500%2F%28600%2Br%29\" hours, the plane has traveled \"%28%28600-r%29%2A1500%29%2F%28600%2Br%29\" kilometers. And there is still 300 kilometers to go. Thus \r
\n" ); document.write( "\n" ); document.write( "\"1500+=+300+%2B+%28%28600-r%29%2A1500%29%2F%28600%2Br%29\"
\n" ); document.write( "==> \"1200+=+%28%28600-r%29%2A1500%29%2F%28600%2Br%29\"
\n" ); document.write( "==> \"4%2F5+=+%28600-r%29%2F%28600%2Br%29\"
\n" ); document.write( "Cross-multiplying, we get
\n" ); document.write( "2400+4r = 3000 - 5r
\n" ); document.write( "==> 9r = 600 ==> r = 66.67 kilometers per hour.\r
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