document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87621>Question 87621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have tried this question for the past hour and I am so lost now that nothing is working.  It states:  find all zeros of the function  X^3+3x^2-x+12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63522 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63522\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find all zeros of the function  X^3+3x^2-x+12<BR>\n" );
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document.write( "Graphing I find x=-4 is a zero<BR>\n" );
document.write( "Using Synthetic Divisionyou can find two other zeroes, as follows:\r<BR>\n" );
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document.write( "-4).....1....3....-1....12<BR>\n" );
document.write( "..........1....-1....3...|..0\r<BR>\n" );
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document.write( "Remainder is zero<BR>\n" );
document.write( "Quotient is x^2-x+3<BR>\n" );
document.write( "Use the quadratic formula to find the zeroes of x^2-x+3<BR>\n" );
document.write( "x = [1+-sqrt(1-4*1*3)]/2\r<BR>\n" );
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document.write( "x = [1+-isqrt(11)]/2\r<BR>\n" );
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document.write( "So the zeroes are x=-4, x= [1+isqrt(11)]/2 and x= [1-isqrt(11)]/2\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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