document.write( "Question 1019204: The personnel manager of a manufacturing company has cross-classified the 400 employees of his company according to their record of absenteeism last year, and whether or not they were smokers, as shown in the following table.
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document.write( "Number of days absent Smoker Nonsmoker
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document.write( "Less than 10 34 260
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document.write( "10 or more 78 28\r
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document.write( "If one of these employees is selected at random.
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document.write( "a. What is the probability that the employee selected was a non-smoker?
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document.write( "b. What is the probability that the employee selected was absent for 10 or more days?
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document.write( "c. Are the events “non-smoker” and “absent less than 10 days” mutually exclusive? Explain.
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document.write( "d. What is the probability that the employee selected was absent for less than 10 days given that the employee is a smoker?
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document.write( "e. What is the probability that the employee selected was absent for less than 10 days given that the employee does not smoke?
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Algebra.Com's Answer #635213 by robertb(5830)![]() ![]() You can put this solution on YOUR website! a. (28+260)/400 = 18/25\r \n" ); document.write( "\n" ); document.write( "b. (78+28)/400 = 53/200\r \n" ); document.write( "\n" ); document.write( "c. The two events are mutually exclusive if P(\"non-smoker\" and \"absent less than 10 days\") = 0. Since from the data, P(\"non-smoker\" and \"absent less than 10 days\") = 260/400 = 13/20, the two events are NOT mutually exclusive.\r \n" ); document.write( "\n" ); document.write( "d. P(\"absent for less than 10 days\"|smoker) = P(\"absent for less than 10 days\" AND smoker)/P(smoker) = \n" ); document.write( "\n" ); document.write( "e. P(\"absent for less than 10 days\"|non-smoker) = P(\"absent for less than 10 days\" AND non-smoker)/P(non-smoker) = |