document.write( "Question 1019208: Use formula for Permutations to calculate in how many ways you can select 2 people out of 10, order of selection makes a difference. \n" ); document.write( "
Algebra.Com's Answer #635208 by Theo(13342)\"\" \"About 
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p(n,x) = n! / (n-x)!\r
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\n" ); document.write( "\n" ); document.write( "n = 10
\n" ); document.write( "x = 2\r
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\n" ); document.write( "\n" ); document.write( "p(n,x) becomes p(10,2) = 10! / (10-2)! = 10! / 8! = (10 * 9 * 8!) / 8!.\r
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\n" ); document.write( "\n" ); document.write( "the 8! in the numerator and denominator cancel out and you are left with:\r
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\n" ); document.write( "\n" ); document.write( "p(10,2) = 10 * 9 = 90\r
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\n" ); document.write( "\n" ); document.write( "in the permutation formula, order makes a difference, so sets with the same elements but in different order are counted as separate sets.\r
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\n" ); document.write( "\n" ); document.write( "in the combination formula, order does not make a difference, so sets with the same elements are only counted.\r
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\n" ); document.write( "\n" ); document.write( "this can be seen easily when dealing with a smaller number of permutations and combinations.\r
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\n" ); document.write( "\n" ); document.write( "assume n = 3 and x = 2.\r
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\n" ); document.write( "\n" ); document.write( "permutation formula ia p(n,x) = n! / (n-x)!\r
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\n" ); document.write( "\n" ); document.write( "combination formula is c(n,x) = n! / (x! * (n-x)!)\r
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\n" ); document.write( "\n" ); document.write( "that extra division by x! in the combinattion formula takes away the multiple ordered versions of the same set.\r
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\n" ); document.write( "\n" ); document.write( "p(3,2) = 3! / 1! = 3*2 = 6\r
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\n" ); document.write( "\n" ); document.write( "c(3,2) = 3! / (2! * 1!) = (3*2)/2 = 3\r
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\n" ); document.write( "\n" ); document.write( "assume the elements are a, b, and c.\r
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\n" ); document.write( "\n" ); document.write( "the number of permutations of 2 out of the 3 elements are detailed below:\r
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\n" ); document.write( "\n" ); document.write( "ab
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\n" ); document.write( "\n" ); document.write( "even though ab and ba have the same elements, they are in a different order and counted separately.\r
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\n" ); document.write( "\n" ); document.write( "the number of combinations of 2 out of the 3 elements are detailed below:\r
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\n" ); document.write( "\n" ); document.write( "ab
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\n" ); document.write( "\n" ); document.write( "ba and ca and cb are not counted as separate sets because they are the same elements shown above but in a different order.\r
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