document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019207>Question 1019207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> for a given interest rate, simple interest varies jointly as the principal and time. If $3000 left in an account for 4 years earned interest of $960 then how much interest would be earned in 7 years </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635186 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635186\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The simple interest formula is I = Prt.\r<BR>\n" );
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document.write( "Now here, P = 3000, t = 4, and I = 960.  Substituting these values into the formula, we get <BR>\n" );
document.write( "960 = 3000*r*4<BR>\n" );
document.write( "==> r = 2/25,or in percent, 8%.\r<BR>\n" );
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document.write( "Thus, the interest earned after 7 years would be \r<BR>\n" );
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document.write( "I = 3000*0.08*7 = $1,680.<BR>\n" );
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