document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1019176>Question 1019176</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The half life of carbon-14 is 5770 years. If I start with 1gram of carbon-14, how long will it take for only 0.25grams to remain? If I start with 25 grams of carbon find a formula that gives the amount of carbon left after t years. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #635124 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=635124\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mathematics or algebra will work about the same, for any exponential decay example.  Study this video for guidance:<BR>\n" );
document.write( "<a  rel=nofollow HREF=\"https://www.youtube.com/watch?v=KbQquygaIPo\">exponential decay, video example</a> </SPAN>\n" );
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