document.write( "Question 1018952: Mrs. Stevens invested a certain amount of money at 7% and twice that amount at 10%. If the combined annual income from both investments us $810, how much was invested at each rate. \n" ); document.write( "
Algebra.Com's Answer #635053 by fractalier(6550)\"\" \"About 
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Call the amount of money invested at 7%, x.
\n" ); document.write( "Thus he invested 2x at 10%.
\n" ); document.write( "The setup looks like this
\n" ); document.write( ".07x + (.10)(2x) = 810
\n" ); document.write( ".07x + .20x = 810
\n" ); document.write( ".27x = 810
\n" ); document.write( "x = 810/.27 = $3000 at 7% and then
\n" ); document.write( "2x = $6000 at 10%
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