document.write( "Question 1019023: Are there m, n, k so that:
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document.write( "1/m + 1/n + 1/k = 1/(m+n) + 1/(n+k) + 1/(m+k) ? \n" );
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Algebra.Com's Answer #635026 by ikleyn(52778)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Are there m, n, k so that: \n" ); document.write( "1/m + 1/n + 1/k = 1/(m+n) + 1/(n+k) + 1/(m+k) ? \n" ); document.write( "------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "First addend in the right side is LESS than first addend in the left side.\r\n" ); document.write( "\r\n" ); document.write( "Second addend in the right side is LESS than second addend in the left side.\r\n" ); document.write( "\r\n" ); document.write( "Third addend in the right side is LESS than third addend in the left side.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Hence, what?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hence, this equation does not have solutions in positive numbers.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |