document.write( "Question 1018797: 18) In a box there are 8 red and 6 blue markers. How many ways can you select 3 markers if:
\n" );
document.write( "(a) exactly 1 red is selected?
\n" );
document.write( "(b) no more than 2 blue are selected?
\n" );
document.write( "(c) there are more blue than red selected?\r
\n" );
document.write( "\n" );
document.write( "I'm not sure where to begin can you please guide me through? \n" );
document.write( "
Algebra.Com's Answer #634869 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! 8 ways to select one red. \n" ); document.write( "6C2 ways to select 2 blue \n" ); document.write( "that is 15. \n" ); document.write( "numbering the blues 1 through 6 \n" ); document.write( "12 \n" ); document.write( "13 \n" ); document.write( "14 \n" ); document.write( "15 \n" ); document.write( "16 \n" ); document.write( "23 \n" ); document.write( "24 \n" ); document.write( "25 \n" ); document.write( "26 \n" ); document.write( "34 \n" ); document.write( "35 \n" ); document.write( "36 \n" ); document.write( "45 \n" ); document.write( "46 \n" ); document.write( "56 \n" ); document.write( "So the number of ways are 8*15=120 \n" ); document.write( "no more than two blue mean 15 ways for 2+6 ways for 1+the number of ways one can select 3 from 8 red (0 blue). That is 8C3 or 56 ways, so the total is 15+6+56=77 ways. \n" ); document.write( "---------------------- \n" ); document.write( "more blue than red. \n" ); document.write( "3 blue and 0 red. That is 6C3=20 ways. 6C3 is the number of ways one can select 3 items from 6. It si 6!/3!/3!, or 6*5*4*3!/3!3! \n" ); document.write( "2 blue and 1 red. That is 6C2*8=120 ways and the total is 140 ways. \n" ); document.write( " \n" ); document.write( " |