document.write( "Question 1018800: A single fair die is tossed once. Let Y be the number facing up. Find the expected value and variance of Y \n" ); document.write( "
Algebra.Com's Answer #634866 by Boreal(15235)\"\" \"About 
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Expected value= x*p(x)
\n" ); document.write( "it is (1/6)(1+2+3+4+5+6)=3.5
\n" ); document.write( "variance is
\n" ); document.write( "sum of (x-mean)^2/n
\n" ); document.write( "(1/6)(2.5^2+1.5^2+0.5^2+0.5^2+1.5^2+2.5^2)=
\n" ); document.write( "(1/6)*17.50=2.92
\n" ); document.write( "E(x)=3.5
\n" ); document.write( "V(x)=2.92
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