document.write( "Question 1018714: The period of a pendulum is equal to 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity. If the length of the pendulum is 40 m and the acceleration due to gravity is 10 m/s^2, what is the period of the pendulum? \n" ); document.write( "
Algebra.Com's Answer #634761 by ikleyn(52879)\"\" \"About 
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\n" ); document.write( "The period of a pendulum is equal to 2π√(l/g), where l is the length of the pendulum and g is the acceleration due to gravity.
\n" ); document.write( "If the length of the pendulum is 40 m and the acceleration due to gravity is 10 m/s^2, what is the period of the pendulum?
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\n" ); document.write( "\n" ); document.write( "T = \"2%2Api%2Asqrt%28L%2Fg%29\" = \"2%2A3.14%2Asqrt%2840%2F10%29\" = 2*3.14*2 = . . . (?)\r
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\n" ); document.write( "\n" ); document.write( "Please calculate it yourself.\r
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