document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1018674>Question 1018674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 2 less than twice its length. If the area of the rectangle is 137 cm2, what is the length of the diagonal? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634725 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634725\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The width of a rectangle is 2 less than twice its length. <BR>\n" );
document.write( "If the area of the rectangle is 137 cm2, what is the length of the diagonal? \r<BR>\n" );
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document.write( "Width = 2x - 2\r<BR>\n" );
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document.write( "Length = x\r<BR>\n" );
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document.write( "Area = 137 cm^2\r<BR>\n" );
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document.write( "137 = x(2x - 2)\r<BR>\n" );
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document.write( "Solve for x.\r<BR>\n" );
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document.write( "Then plug your x value into x and 2x - 2.\r<BR>\n" );
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document.write( "Finally, use the Pythagorean Theorem to\r<BR>\n" );
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document.write( "find the hypotenuse. \r<BR>\n" );
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document.write( "You take it from here.<BR>\n" );
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