document.write( "Question 1018609: Find two consecutive integers such that the larger is nine more than twice the smaller \n" ); document.write( "
Algebra.Com's Answer #634705 by toddcarnes(6)\"\" \"About 
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Question: Find two consecutive integers such that the larger is nine more than twice the smaller.\r
\n" ); document.write( "\n" ); document.write( "Answer: \r
\n" ); document.write( "\n" ); document.write( "Let x be your first integer.
\n" ); document.write( "Then x + 1 will be the next consecutive integer.\r
\n" ); document.write( "\n" ); document.write( "Create the equation given in the original problem...\r
\n" ); document.write( "\n" ); document.write( "(x+1) = 2x + 9\r
\n" ); document.write( "\n" ); document.write( "Solve for x...\r
\n" ); document.write( "\n" ); document.write( "x + 1 = 2x + 9
\n" ); document.write( "1 = x + 9
\n" ); document.write( "x = -8\r
\n" ); document.write( "\n" ); document.write( "If x = -8, then (x+1) = -7.\r
\n" ); document.write( "\n" ); document.write( "Therefore the two consecutive integers you are looking for are -8 and -7.
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