document.write( "Question 1018586: At a family gathering there are 100 people. There are 4 less than twice as many women as men and 6 more children as both combined. How many children are at the gathering? \n" ); document.write( "
Algebra.Com's Answer #634670 by JulietG(1812)![]() ![]() You can put this solution on YOUR website! Let W = women, M = men, C = children \n" ); document.write( "W + M + C = 100 \n" ); document.write( "W = 2M - 4 (the wording is odd???) \n" ); document.write( "C = 2(W + M) + 6 \n" ); document.write( "Therefore, C = 2W + 2M + 6 \n" ); document.write( "Go back to the top equation \n" ); document.write( "W + M + (2W + 2M + 6) = 100 \n" ); document.write( "3W + 3M + 6 = 100 \n" ); document.write( "3W + 3M = 94 \n" ); document.write( "Substitute the known value of W \n" ); document.write( "3(2M-4) + 3M = 94 \n" ); document.write( "6M - 12 + 3M = 94 \n" ); document.write( "9M -12 = 94 \n" ); document.write( "9M = 106 \n" ); document.write( "M = 11.77 \n" ); document.write( "Hmmmm...can't have part of a man \n" ); document.write( "Can you check the wording to the problem and type is exactly as written? This sentence is odd: There are 4 less than twice as many women as men and 6 more children as both combined. \n" ); document.write( " \n" ); document.write( " |