document.write( "Question 1018423: the length of a rectangle is 2 feet less than three times the width. the area of the rectangle is 40 square feet. find the length and the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #634666 by Cromlix(4381)\"\" \"About 
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Hi there,
\n" ); document.write( "Make width = 'x'
\n" ); document.write( "Length therefore, = 3x - 2
\n" ); document.write( "Area = Width * Length (* Times)
\n" ); document.write( "40 = x(3x - 2)
\n" ); document.write( "40 = 3x^2 - 2x
\n" ); document.write( "3x^2 - 2x - 40 = 0
\n" ); document.write( "Factorise
\n" ); document.write( "(3x + 10)(x - 4) = 0
\n" ); document.write( "3x + 10 = 0
\n" ); document.write( "3x = -10
\n" ); document.write( "x = -10/3 (Disregard as -ve)
\n" ); document.write( "x - 4 = 0
\n" ); document.write( "x = 4
\n" ); document.write( "Width = 4 feet
\n" ); document.write( "Length = 10 feet.
\n" ); document.write( "Hope this helps :-)
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