document.write( "Question 1018570: sec(-7pi/12)
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Algebra.Com's Answer #634663 by stanbon(75887)\"\" \"About 
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sec(-7pi/12)
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\n" ); document.write( "sec(-7pi/12) = 1/[cos(-7pi/12)]
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\n" ); document.write( "= 1/[cos(-3pi/12)-4pi/12]
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\n" ); document.write( "= 1/[cos(-pi/4 +(-pi/3))]
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\n" ); document.write( "= 1/[cos(-pi/4)*cos(-pi/3) - sin(-pi/4)*sin(-pi/3)]
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\n" ); document.write( "= 1/[(sqrt(2)/2)(1/2) - (-sqrt(2)/2)(-sqrt(3)/2))
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\n" ); document.write( "= 1/[(sqrt(2)/4) - (sqrt(6))/4]
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\n" ); document.write( "= 4/[sqrt(2)-sqrt(6)]
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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