document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1018435>Question 1018435</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive even integers such that the sum of twice the first, four times the second, and three times the third is 398<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634662 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "3 consecutive even integers<BR>\n" );
document.write( "n, n + 2 and n + 4.<BR>\n" );
document.write( "2(n) + 4(n + 2) + 3(n + 4) = 398<BR>\n" );
document.write( "2n + 4n + 8 + 3n + 12 = 398<BR>\n" );
document.write( "Collect like terms<BR>\n" );
document.write( "2n + 4n + 3n + 398 - 8 - 12<BR>\n" );
document.write( "9n = 378<BR>\n" );
document.write( "n = 42<BR>\n" );
document.write( "42, 44, 46<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "2(42) + 4(44) + 3(46) = 398<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
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