document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1018558>Question 1018558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $1,925. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $610. (Round z-score computation to 2 decimal places and your final answers to 2 decimal places.)<BR>\n" );
document.write( " <BR>\n" );
document.write( "a.	What percent of the adults spend more than $2,725 per year on reading and entertainment?<BR>\n" );
document.write( " <BR>\n" );
document.write( "  Percent	 %  <BR>\n" );
document.write( " <BR>\n" );
document.write( "b.	What percent spend between $2,725 and $3,125 per year on reading and entertainment?<BR>\n" );
document.write( " <BR>\n" );
document.write( "  Percent	 %  <BR>\n" );
document.write( " <BR>\n" );
document.write( "c.	What percent spend less than $1,300 per year on reading and entertainment?<BR>\n" );
document.write( " <BR>\n" );
document.write( "  Percent	 %  <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634651 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> According to a government study among adults in the 25- to 34-year age group, the mean amount spent per year on reading and entertainment is $1,925. Assume that the distribution of the amounts spent follows the normal distribution with a standard deviation of $610. (Round z-score computation to 2 decimal places and your final answers to 2 decimal places.)\r<BR>\n" );
document.write( "\n" );
document.write( "a.	What percent of the adults spend more than $2,725 per year on reading and entertainment?<BR>\n" );
document.write( "-------<BR>\n" );
document.write( "z(2725) = (2725-1925)/610 = 1.3115<BR>\n" );
document.write( "------<BR>\n" );
document.write( "P(x > 2725) = P(z > 1.3115) = normalcdf(1.3115,100) = 0.0948<BR>\n" );
document.write( "-------------------------------------\r<BR>\n" );
document.write( "\n" );
document.write( "Percent	% = 9.48%<BR>\n" );
document.write( "-----------------------<BR>\n" );
document.write( "=============================== \r<BR>\n" );
document.write( "\n" );
document.write( "b.	What percent spend between $2,725 and $3,125 per year on reading and entertainment?<BR>\n" );
document.write( "Using the TI-84 normalcdf function::<BR>\n" );
document.write( "normalcdf(2725,3125,1925,610) = 0.0703\r<BR>\n" );
document.write( "\n" );
document.write( "Percent	% = 7.03%<BR>\n" );
document.write( "--------------------------- \r<BR>\n" );
document.write( "\n" );
document.write( "c.	What percent spend less than $1,300 per year on reading and entertainment?\r<BR>\n" );
document.write( "\n" );
document.write( "Percent	%<BR>\n" );
document.write( "Find the z value of 1300; Find the Probability of z less then that <BR>\n" );
document.write( "z value.<BR>\n" );
document.write( "------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "-----------  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );