document.write( "Question 1018522: Dan's Mobile Window Tinting tints car windows. Dan has determined his company's weekly revenue and cost functions as follows:
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document.write( "R(w) = 37w + 8
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document.write( "C(w) = 27w + 688
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document.write( "where R(w) represents the weekly revenue in dollars from tinting w windows and C(w) represents the weekly cost in dollars to tint w windows. Find the number of windows Dan must tint each week to break even or make a profit.\r
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document.write( "Dan must tint at least ______ windows to break even or make a profit.
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Algebra.Com's Answer #634635 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Dan's Mobile Window Tinting tints car windows. \n" ); document.write( " Dan has determined his company's weekly revenue and cost functions as follows: \n" ); document.write( "R(w) = 37w + 8 \n" ); document.write( "C(w) = 27w + 688 \n" ); document.write( "where R(w) represents the weekly revenue in dollars from tinting w windows and C(w) represents the weekly cost in dollars to tint w windows. \n" ); document.write( " Find the number of windows Dan must tint each week to break even or make a profit. \n" ); document.write( "Dan must tint at least ______ windows to break even or make a profit. \n" ); document.write( ": \n" ); document.write( "Break even point is when revenue = cost; R(w) = C(w); therfore \n" ); document.write( "37w + 8 = 27w + 688 \n" ); document.write( "37w - 27w = 688 - 8 \n" ); document.write( "10w = 680 \n" ); document.write( "w = 680/10 \n" ); document.write( "w = 68 windows required to break even \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "see if this is true, find the actual $$ for each, should be equal \n" ); document.write( "R(w) = 37(68) + 8 \n" ); document.write( "R(w) = 2516 + 8 \n" ); document.write( "R(w) = 2524 \n" ); document.write( ": \n" ); document.write( "C(w) = 27(68) + 688 \n" ); document.write( "C(w) = 1836 = 688 \n" ); document.write( "C(w) = 2524 \n" ); document.write( " |