document.write( "Question 1018537: 2x^2 + 6 = -7x\r
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document.write( "factoring \n" );
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Algebra.Com's Answer #634615 by addingup(3677)![]() ![]() You can put this solution on YOUR website! Add 7x on both sides: \n" ); document.write( "2x^2+7x+6 = 0 \n" ); document.write( "Now factor the left side \n" ); document.write( "(x+2)(2x+3) = 0 \n" ); document.write( "Since you seem to be having trouble factoring (I think I just answered another one of your questions) here is more on the subject: \n" ); document.write( "Our equation will have three elements and one unknown in the form ax^2+bx+c so it will be a quadratic. Note that not all equations can be factored. \n" ); document.write( "To factor a number, we multiply them in FOIL:First, Outer, Inner, Last. \n" ); document.write( "To get 2x^2 we need First two numbers that when multiplied will produce this result: \n" ); document.write( "(x__)(2x__) \n" ); document.write( "Now we need Outer and Inner to add up to 7x, keeping in mind that Last includes Inner: \n" ); document.write( "(x+2)(2x+3) \n" ); document.write( "As you see, the Outers are x on the left and 3 on the right, multiplied = 3x. And our Inner is 2*2x= 4x Add it to the Outer:4x+3x= 7x. So we got our middle number. \n" ); document.write( "Finally we have Last:2*3= 6, and this is the 6 we need to complete our original equation. \n" ); document.write( "Factoring takes a lot of practice and trial-and-error. Be patient and apply yourself. \n" ); document.write( "Best of luck, \n" ); document.write( "J \n" ); document.write( " \n" ); document.write( " |