document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10647>Question 10647</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the card game Bridge, a yarborough is a 13-card hand containing only cards numbered 2 through 9. Find the number of ways in which to get a yarborough. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #6346 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=6346\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The possibility of a hand of bridge is C(52,13).\r<BR>\n" );
document.write( "\n" );
document.write( " Among a deck of 52 cards, there are 32 =(8*4) cards between 2 & 9.<BR>\n" );
document.write( " So, there are C(32,13) possibilities of a yarborough hand.\r<BR>\n" );
document.write( "\n" );
document.write( " Hence, the probability for a yarborough hand is<BR>\n" );
document.write( "  C(32,13)/C(52,13) [ you can leave the answer like that]<BR>\n" );
document.write( "   = 0.000547033  [by using the function combin(n, r) in MS Excel ]\r<BR>\n" );
document.write( "\n" );
document.write( " Kenny<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );