document.write( "Question 1018441: Solve
\n" ); document.write( "sqrt(b+1)=sqrt(b+6) -1
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Algebra.Com's Answer #634540 by addingup(3677)\"\" \"About 
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Solve for b:
\n" ); document.write( "\"sqrt%28b%2B1%29+=+sqrt%28b%2B6%29-1\"
\n" ); document.write( "Get rid of the square root on the left, raise both sides to the power of two:
\n" ); document.write( "(((b+1 = (sqrt(b+6)-1)^2}}}
\n" ); document.write( "Subtract \"%28sqrt%28b%2B6%29-1%29%5E2\" from both sides in order to move everything to the left side:
\n" ); document.write( "\"1%2Bb-%28sqrt%28b%2B6%29-1%29%5E2+=+0\"
\n" ); document.write( "Expand the terms on the left and you get:
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\n" ); document.write( "Divide both sides by 2:
\n" ); document.write( "\"sqrt%28b%2B6%29+=+3\"
\n" ); document.write( "Raise both sides to the power of two to get rid of the square root:
\n" ); document.write( "b+6 = 9
\n" ); document.write( "Subtract 6 from both sides:
\n" ); document.write( "b = 3
\n" ); document.write( "Happy learning,
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