document.write( "Question 1018389: I'm thrice as old as you were, when I was as old as you are. Our current ages add up to 80. How old are you and me ? \n" ); document.write( "
Algebra.Com's Answer #634522 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! let m = the 1st guy \n" ); document.write( "let y = the other guy \n" ); document.write( "let d = (m - y), the difference in their ages \n" ); document.write( ": \n" ); document.write( " I'm thrice as old as you were, when I was as old as you are. \n" ); document.write( "m = 3(y - d) \n" ); document.write( "Replace d with (m-y) \n" ); document.write( "m = 3(y - (m-y)) \n" ); document.write( "remove brackets \n" ); document.write( "m = 3(y - m + y) \n" ); document.write( "m = 3(2y - m) \n" ); document.write( "m = 6y - 3m \n" ); document.write( "m + 3m = 6y \n" ); document.write( "4m = 6y \n" ); document.write( "Simplify, divide by 2 \n" ); document.write( "2m = 3y \n" ); document.write( ": \n" ); document.write( " Our current ages add up to 80. How old are you and me ? \n" ); document.write( "m + y = 80 \n" ); document.write( "y = -m + 80 \n" ); document.write( "replace y in the equation 2m = 3y, with (-m+80) \n" ); document.write( "2m = 3(-m+80) \n" ); document.write( "2m = -3m + 240 \n" ); document.write( "2m + 3m = 240 \n" ); document.write( "5m = 240 \n" ); document.write( "m = 240/5 \n" ); document.write( "m = 48 yrs is the 1st guys age \n" ); document.write( "Find y \n" ); document.write( "y = -48 + 80 \n" ); document.write( "y = 32 yrs is the 2nd guys age \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this: 48 - 32 = 16 is the difference in their ages \n" ); document.write( "\"I'm thrice as old as you were, when I was as old as you are.\" \n" ); document.write( "16 yrs ago the 1st guy was 32, the 2nd guy was 16 \n" ); document.write( "48 = 3(32 - 16) \n" ); document.write( " |