document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1018347>Question 1018347</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A concrete pipe, 2.44 meters long has for its outside diameter 533 mm. and inside diameter of 425 mm. Find the amount of concrete used in manufacturing 1,000 concrete pipes. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634515 by </B><A HREF=/tutors/aboutme.mpl?userid=Cromlix><B>Cromlix(4381)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Cromlix><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Cromlix><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634515\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hi there,<BR>\n" );
document.write( "2.44 meters = 244 centimeters<BR>\n" );
document.write( "533 millimeters = 53.3 centimeters<BR>\n" );
document.write( "425 millimeters = 42.5 centimeters<BR>\n" );
document.write( "Using outside radius (53.3/2 = 26.65 centimeters)<BR>\n" );
document.write( "Volume = Pi x radius^2 x height(length)<BR>\n" );
document.write( "Volume = Pi x 26.25^2 x 244 = 528199.8998 cm^3<BR>\n" );
document.write( "Using inside radius (42.5/2 = 21.25)<BR>\n" );
document.write( "Volume = Pi x radius^2 x height(length)<BR>\n" );
document.write( "Volume = Pi x 21.25^2 x 244 = 346144.6056 cm^3<BR>\n" );
document.write( "528199.8998 - 346144.6056<BR>\n" );
document.write( "= 182055.2942 cm^3 This is the thickness of the pipe<BR>\n" );
document.write( "The amount of concrete to make 1 pipe.<BR>\n" );
document.write( "= 182.055 litres<BR>\n" );
document.write( "1000 pipes = 182.055 x 1000<BR>\n" );
document.write( "182055 litres of concrete.<BR>\n" );
document.write( "Hope this helps :-) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );