document.write( "Question 1018390: At 9AM a train traveling 60 miles per hour leaves Los Angeles for San Francisco, a distance of 400 miles. At noon a car traveling at an average speed of 40 miles per hour leaves San Francisco for Los Angeles. At what time will the two vehicles pass each other? Please help! I know I need to draw a graph,but I am having trouble with writing an equation! \n" ); document.write( "
Algebra.Com's Answer #634514 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! At 9AM a train traveling 60 miles per hour leaves Los Angeles for San Francisco, a distance of 400 miles. At noon a car traveling at an average speed of 40 miles per hour leaves San Francisco for Los Angeles. \n" ); document.write( "At what time will the two vehicles pass each other? \n" ); document.write( "----- \n" ); document.write( "LA to SanFran DATA: \n" ); document.write( "rate = 60 mph ; distance = x miles ; time = d/r = x/60 hrs \n" ); document.write( "----------------- \n" ); document.write( "SanFran to LA DATA: \n" ); document.write( "rate = 40 mph ; tistance = 400-x ; time = d/r = (400-x)/40 hrs \n" ); document.write( "-------- \n" ); document.write( "Equation: \n" ); document.write( "to SF time = to LA time + 3 hrs \n" ); document.write( "---------------------------------------- \n" ); document.write( "x/60 = (400-x)/40 + 3 hrs \n" ); document.write( "- \n" ); document.write( "40x = 60(400-x) + 3*60*40 \n" ); document.write( "------------------------------------ \n" ); document.write( "40x = 24000 - 60x + 7200 \n" ); document.write( "-------------- \n" ); document.write( "100x = 31200 \n" ); document.write( "---- \n" ); document.write( "x = 312 miles (distance of LA to SF car) \n" ); document.write( "time = 312 miles/60 mph = 5.2 hrs \n" ); document.write( "clock time = 9+5.2 = 14.2 = 2:12PM \n" ); document.write( "------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " \n" ); document.write( " |