document.write( "Question 1018359: what is the perimeter of a rectangle with an area of 33 2/9 ft squared and a length of 8 2/3 ft? \n" ); document.write( "
Algebra.Com's Answer #634503 by Cromlix(4381)\"\" \"About 
You can put this solution on YOUR website!
Hi there,
\n" ); document.write( "Convert 33 2/9 to ninths = 299/9
\n" ); document.write( "Convert 8 2/3 to thirds = 26/3
\n" ); document.write( "299/9 divided by 26/3
\n" ); document.write( "= 299/9 x 3/26
\n" ); document.write( "= 299/78 = 23/6
\n" ); document.write( "Width = 23/6 ft
\n" ); document.write( "Length = 26/3 ft
\n" ); document.write( "Perimeter = 2(Width) + 2(Length)
\n" ); document.write( "Perimeter = 2(23/6) + 2(26/3)
\n" ); document.write( "Perimeter = 23/3 + 52/3
\n" ); document.write( "Perimeter = 75/3
\n" ); document.write( "Perimeter = 25 ft.
\n" ); document.write( "Hope this helps :-)
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