document.write( "Question 1018359: what is the perimeter of a rectangle with an area of 33 2/9 ft squared and a length of 8 2/3 ft? \n" ); document.write( "
Algebra.Com's Answer #634503 by Cromlix(4381)![]() ![]() You can put this solution on YOUR website! Hi there, \n" ); document.write( "Convert 33 2/9 to ninths = 299/9 \n" ); document.write( "Convert 8 2/3 to thirds = 26/3 \n" ); document.write( "299/9 divided by 26/3 \n" ); document.write( "= 299/9 x 3/26 \n" ); document.write( "= 299/78 = 23/6 \n" ); document.write( "Width = 23/6 ft \n" ); document.write( "Length = 26/3 ft \n" ); document.write( "Perimeter = 2(Width) + 2(Length) \n" ); document.write( "Perimeter = 2(23/6) + 2(26/3) \n" ); document.write( "Perimeter = 23/3 + 52/3 \n" ); document.write( "Perimeter = 75/3 \n" ); document.write( "Perimeter = 25 ft. \n" ); document.write( "Hope this helps :-) \n" ); document.write( " |