document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1018319>Question 1018319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two numbers given that their sum is 48 and the smaller number is equal to one fifth of the larger number<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634486 by </B><A HREF=/tutors/aboutme.mpl?userid=clearblueskai><B>clearblueskai(22)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=clearblueskai><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=clearblueskai><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634486\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the smaller number and y the larger number\r<BR>\n" );
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document.write( "x + y = 48<BR>\n" );
document.write( "x = 1/5y\r<BR>\n" );
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document.write( "substitute the second equation to the first equation<BR>\n" );
document.write( "(1/5y) + y = 48<BR>\n" );
document.write( "6/5 y = 48\r<BR>\n" );
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document.write( "Multiply  both sides by 5/6 to cancel the numerical coefficient 6/5<BR>\n" );
document.write( "y =  (48)(5/6)<BR>\n" );
document.write( "y = 40\r<BR>\n" );
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document.write( "x + 40 = 48<BR>\n" );
document.write( "x = 48 - 40<BR>\n" );
document.write( "x = 8\r<BR>\n" );
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document.write( "smaller number is 8 <BR>\n" );
document.write( "larger number is 40 </SPAN>\n" );
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