document.write( "Question 1018259: Last year, Alonzo had
\n" ); document.write( "$20,000
\n" ); document.write( " to invest. He invested some of it in an account that paid
\n" ); document.write( "6%
\n" ); document.write( " simple interest per year, and he invested the rest in an account that paid
\n" ); document.write( "10%
\n" ); document.write( " simple interest per year. After one year, he received a total of
\n" ); document.write( "$1280
\n" ); document.write( " in interest. How much did he invest in each account? \n" ); document.write( "
Algebra.Com's Answer #634481 by addingup(3677)\"\" \"About 
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He had 20,000
\n" ); document.write( "Invested x at 6%
\n" ); document.write( "Invested 20,000-x at 10%
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\n" ); document.write( "0.06x+0.10(20,000-x) = 1280
\n" ); document.write( "0.06x+2,000-0.10x = 1280
\n" ); document.write( "-0.04x = -720 divide, and remember -/- = +
\n" ); document.write( "x = 18,000 so this is at 6% and
\n" ); document.write( "20,000-18,000 = 2,000 is invested at 10%
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\n" ); document.write( "Check:
\n" ); document.write( "18,000(0.06) = 1,080
\n" ); document.write( "2,000(0.10) = 200
\n" ); document.write( "_______________-----------
\n" ); document.write( "Total. . . . . . 1,280 we have the correct answer
\n" ); document.write( "J \n" ); document.write( "
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