document.write( "Question 87487: Please HELP!!
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document.write( "3 loaves of bread and 2 jars of peanut butter cost $5.49. 4 loaves of bread and 3 jars of peanut butter cost $7.75. Find the price of a loaf of bread and a jar of peanut butter. \n" );
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Algebra.Com's Answer #63442 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=price of a loaf of bread \n" ); document.write( "And y=cost of a jar of peanut butter\r \n" ); document.write( "\n" ); document.write( "Now we are told that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x+2y=$5.49-------------------------------------------------eq1\r \n" ); document.write( "\n" ); document.write( "We are also told that:\r \n" ); document.write( "\n" ); document.write( "4x+3y=$7.75--------------------------------------------------eq2\r \n" ); document.write( "\n" ); document.write( "multiply each term in eq1 by 3 and we get:\r \n" ); document.write( "\n" ); document.write( "9x+6y=$16.47----------------------------------eq1a\r \n" ); document.write( "\n" ); document.write( "multiply each term in eq2 by 2 and we get:\r \n" ); document.write( "\n" ); document.write( "8x+6y=$15.50----------------------------------eq2a\r \n" ); document.write( "\n" ); document.write( "subtract eq2a from eq1a and we have:\r \n" ); document.write( "\n" ); document.write( "x=$0.97--------------------------------price of a loaf of bread\r \n" ); document.write( "\n" ); document.write( "substitute x=$0.97 into eq1 and we have:\r \n" ); document.write( "\n" ); document.write( "3($0.97)+2y=$5.49 get rid of parens\r \n" ); document.write( "\n" ); document.write( "$2.91+2y=$5.49 subtract $2.91 from both sides\r \n" ); document.write( "\n" ); document.write( "$2.91-$2.91+2y=$5.49-$2.91 collect like terms\r \n" ); document.write( "\n" ); document.write( "2y=$2.58 divide both sides by 2\r \n" ); document.write( "\n" ); document.write( "y=$1.29-----------------------------------price of a jar of peanut butter\r \n" ); document.write( "\n" ); document.write( "CK\r \n" ); document.write( "\n" ); document.write( "from eq1:\r \n" ); document.write( "\n" ); document.write( "3($0.97)+2($1.29)=$5.49 \n" ); document.write( "$2.91+$2.58=$5.49 \n" ); document.write( "$5.49=$5.49\r \n" ); document.write( "\n" ); document.write( "from eq2\r \n" ); document.write( "\n" ); document.write( "4($0.97)+3($1.29)=$7.75\r \n" ); document.write( "\n" ); document.write( "$3.88+$3.87=$7.75\r \n" ); document.write( "\n" ); document.write( "$7.75=7.75\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |