document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87511>Question 87511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This question is really troubling me and i could use some help please. Given that “e” is a complex number, solve e + 6&#275; = 7   (note: &#275; is the complex conjugate of e)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63438 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63438\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let e= a+bi, and e(complememt) = a-bi\r<BR>\n" );
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document.write( "What you have is <BR>\n" );
document.write( "e + 6&#275; = 7 <BR>\n" );
document.write( "a+bi + 6(a-bi) = 7 +0i<BR>\n" );
document.write( "a+bi +6a -6bi = 7 + 0i<BR>\n" );
document.write( "7a -5bi = 6 + 0i\r<BR>\n" );
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document.write( "Therefore, 7a= 6, so a=6/7<BR>\n" );
document.write( "and -5b= 0, so b=0\r<BR>\n" );
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document.write( "Therefore, e=6/7 +0i\r<BR>\n" );
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document.write( "R^2  Retired from SCC </SPAN>\n" );
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