document.write( "Question 1018209: the perimeter of a piece of cardboard is 34 inches. squares measuring 2 inches on a side are cut from each corner so that when sides are folded up, the diagonal of the resulting box has length 7 inches. what are the original dimensions of the cardboard? \n" ); document.write( "
Algebra.Com's Answer #634378 by josgarithmetic(39617)\"\" \"About 
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Account for perimeter of the uncut rectangle:
\n" ); document.write( "\"2x%2B2y=34\"
\n" ); document.write( "\"highlight%28x%2By=17%29\" when that equation simplified.\r
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\n" ); document.write( "\n" ); document.write( "The dimensional measurements for the base surface after the four cut squares removed and flaps folded become \"%28x-2%2A2%29\" and \"%28y-2%2A2%29\".\r
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\n" ); document.write( "\n" ); document.write( "The given diagonal value, through the THREE dimensions follows Pythagorean Theorem formula: \"highlight%28%28x-4%29%5E2%2B%28y-4%29%5E2%2B2%5E2=7%5E2%29\", since the diagonal was given as 7.\r
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\n" ); document.write( "\n" ); document.write( "The equations outlined in red color form a system to solve.
\n" ); document.write( "The 3-d diagonal equation should be simplified first...
\n" ); document.write( "\"system%28%28x-4%29%5E2%2B%28y-4%29%5E2=45%2Cx%2By=17%29\", and go from there...
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