document.write( "Question 1018155: A triangle with sides 17cm, 39cm and 44cm contains an inscribed circle with circumference 13 1/5 pi cm. what is the area of part of the triangle that is outside the inscribed circle? Express your answer in terms of pi. \n" ); document.write( "
Algebra.Com's Answer #634375 by KMST(5328)\"\" \"About 
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For a circle of radius \"R\" ,
\n" ); document.write( "\"circumference=2%2Api%2AR\" and
\n" ); document.write( "\"area=pi%2AR%5E2\" ,
\n" ); document.write( "so for the circle in this problem
\n" ); document.write( "\"2%2Api%2AR=13%261%2F5\"\"cm=%2866%2F5%29%2Api\"\"cm\"-->\"R=33%2F5\"\"cm=6.6cm\" , and
\n" ); document.write( "\"area=pi%2A6.6cm%5E2=43.56pi\"\"cm%5E2\" .
\n" ); document.write( "
\n" ); document.write( "For a triangle with side length \"a\" , \"b\" , and \"c\" ,
\n" ); document.write( "the area can be calculated using Heron's formula as
\n" ); document.write( "\"area=sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29\" where \"s\" is the semiperimeter (half the perimeter),
\n" ); document.write( "calculated as \"s=%28a%2Bb%2Bc%29%2F2\" .
\n" ); document.write( "For the triangle in the problem,
\n" ); document.write( "\"s=17cm%2B39cm%2B44cm%29%2F2=100cm%2F2=50cm\" ,
\n" ); document.write( "and the area, in \"cm%5E2\" , is
\n" ); document.write( "\"area=sqrt%2850%2A%2850-17%29%2A%2850-39%29%2A%2850-44%29%29=sqrt%2850%2A33%2A11%2A6%29=330\" .
\n" ); document.write( "So, with the area of the triangle being \"330cm%5E2\"
\n" ); document.write( "and the area of the circle being \"43.56pi\"\"cm%5E2\" ,
\n" ); document.write( "the area of the part of the triangle that is outside the inscribed circle is
\n" ); document.write( "\"330cm%5E2-43.56pi\"\"cm%5E2=highlight%28matrix%281%2C2%2C%28330-43.56pi%29%2Ccm%5E2%29%29\" .
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\n" ); document.write( "IF YOU REALLY HAVE TO USE THE PYTHAGOREAN THEOREM,
\n" ); document.write( "you can solve the triangle as solver did for the same question posted as question number 1018159:
\n" ); document.write( "
\n" ); document.write( "\"green%28h%29=sqrt%2817%5E2-x%5E2%29=sqrt%2839%5E2-%2844-x%29%5E2%29\"
\n" ); document.write( "\"sqrt%2817%5E2-x%5E2%29=sqrt%2839%5E2-%2844-x%29%5E2%29\"
\n" ); document.write( "\"17%5E2-x%5E2=39%5E2-%2844%5E2%2Bx%5E2-88x%29\"
\n" ); document.write( "\"17%5E2-x%5E2=39%5E2-44%5E2-x%5E2%2B88x%29\"
\n" ); document.write( "\"17%5E2=39%5E2-44%5E2%2B88x%29\"
\n" ); document.write( "\"17%5E2-39%5E2%2B44%5E2=88x%29\"
\n" ); document.write( "\"289-1521%2B1936=88x%29\"
\n" ); document.write( "\"704=88x%29\"--->\"x=704%2F88=8\"
\n" ); document.write( "So, \"green%28h%29=sqrt%2817%5E2-8%5E2%29=sqrt%28289-64%29=sqrt%28225%29=15\" ,
\n" ); document.write( "and the area of the triangle, in \"cm%5E2\" is
\n" ); document.write( "\"area=44%2A15%2F2=330\" .
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