document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=87511>Question 87511</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This question is really troubling me and i could use some help please. Given that “e” is a complex number, solve e + 6&#275; = 7   (note: &#275; is the complex conjugate of e)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #63437 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=63437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that “e” is a complex number, solve e + 6&#275; = 7 (note: &#275; is the complex conjugate of e) <BR>\n" );
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document.write( "If e is a complex number, e = a + bi<BR>\n" );
document.write( "If e-bar is its conjugate, e-bar = a-bi<BR>\n" );
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document.write( "Substituting:<BR>\n" );
document.write( "a+bi + 6(a-bi) = 7<BR>\n" );
document.write( "7a -5bi =7 + 0i<BR>\n" );
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document.write( "7a = 7, so a = 1<BR>\n" );
document.write( "-5b = 0, so b = 0<BR>\n" );
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document.write( "So e = 1 + 0i <BR>\n" );
document.write( "e = 1<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H. \r<BR>\n" );
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