document.write( "Question 1018176: The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 24 cm^2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #634337 by stanbon(75887) ![]() You can put this solution on YOUR website! The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 24 cm^2, what is the length of the diagonal? \n" ); document.write( "-------------- \n" ); document.write( "length = \"x\" \n" ); document.write( "width = \"2x-6\" \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "x(2x-6) = 24 \n" ); document.write( "----- \n" ); document.write( "2x^2 - 6x - 24 = 0 \n" ); document.write( "x^2-3x-12 = 0 \n" ); document.write( "--------- \n" ); document.write( "x = [3+-sqrt(9-4*-12)]/2 \n" ); document.write( "--------- \n" ); document.write( "x = length = [3+-sqrt(57)]/2 \n" ); document.write( "----- \n" ); document.write( "width = 2[length]-6 \n" ); document.write( "----------------- \n" ); document.write( "diagonal = sqrt[length^2 + width^2] \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |