document.write( "Question 1018176: The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 24 cm^2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #634337 by stanbon(75887)\"\" \"About 
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The width of a rectangle is 6 less than twice its length. If the area of the rectangle is 24 cm^2, what is the length of the diagonal?
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\n" ); document.write( "length = \"x\"
\n" ); document.write( "width = \"2x-6\"
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\n" ); document.write( "Equation:
\n" ); document.write( "x(2x-6) = 24
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\n" ); document.write( "2x^2 - 6x - 24 = 0
\n" ); document.write( "x^2-3x-12 = 0
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\n" ); document.write( "x = [3+-sqrt(9-4*-12)]/2
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\n" ); document.write( "x = length = [3+-sqrt(57)]/2
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\n" ); document.write( "width = 2[length]-6
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\n" ); document.write( "diagonal = sqrt[length^2 + width^2]
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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