document.write( "Question 1018149: A biomedical research company produces 49% of its insulin at a plant in Kansas City, and the remainder is produced at a plant in Jefferson City. Quality control has shown that 1.1% of the insulin produced at the plant in Kansas City is defective, while 0.65% of the insulin produced at the plant in Jefferson City is defective. What is the probability that a randomly chosen unit of insulin came from the plant in Jefferson City given that it is defective? \n" ); document.write( "
Algebra.Com's Answer #634308 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! Make a table, which makes it easier. Use large numbers to limit decimals \n" ); document.write( "place=====good======defective===total \n" ); document.write( "JC========9935========65=======10000 \n" ); document.write( "KC========9890=======110=======10000 \n" ); document.write( "BUT, they aren't equal, so I will increase to 100,000 and make JC 51000 \n" ); document.write( "=========50668.5=====331.5=====51000; multiplying the above cells by 5.1 \n" ); document.write( "=========48461=======539=======49000; multiplying the above b 4.9 \n" ); document.write( "=========98129.5=====870.5====100000 \n" ); document.write( "Given that the part is defective (870.5 out of 100000), the probability it came from JC is 331.5/870.5=0.3808 \n" ); document.write( "Intuitively it is a little more likely because a little more is made there; however, it is less than 2/3s as likely on a per unit basis, so the probability should be less than half. \n" ); document.write( " \n" ); document.write( " |