document.write( "Question 1018106: Nico is saving money for his college education. He invests some money at 8%, and $1900 less than that amount at 3 %. The investments produced a total of $240 interest in 1 yr. How much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #634268 by fractalier(6550)![]() ![]() You can put this solution on YOUR website! Call how much Nico invests at 8%, x. \n" ); document.write( "Then the amount invested at 3% must be x - 1900. \n" ); document.write( "The setup looks like this \n" ); document.write( ".08x + .03(x - 1900) = 240 \n" ); document.write( "We then distribute and solve for x... \n" ); document.write( ".08x + .03x - 57 = 240 \n" ); document.write( ".11x - 57 = 240 \n" ); document.write( ".11x = 297 \n" ); document.write( "Now divide by .11 and get \n" ); document.write( "x = 297 / .11 = $2700 at 8% \n" ); document.write( "and thus $1900 less means \n" ); document.write( "$800 at 3%... \n" ); document.write( " |