document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1018019>Question 1018019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 2 numbers is 5. 5 times the larger number plus 4 times the smaller number is 38. Find the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634256 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634256\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Call the larger and smaller numbers, x and y.<BR>\n" );
document.write( "Then we have<BR>\n" );
document.write( "x + y = 5<BR>\n" );
document.write( "and <BR>\n" );
document.write( "5x + 4y = 38<BR>\n" );
document.write( "A few ways to do this, so here's one...<BR>\n" );
document.write( "If x + y = 5, then y = 5 - x<BR>\n" );
document.write( "Now substitute and get<BR>\n" );
document.write( "5x + 4(5-x) = 38<BR>\n" );
document.write( "5x + 20 - 4x = 38<BR>\n" );
document.write( "x + 20 = 38<BR>\n" );
document.write( "x = 18<BR>\n" );
document.write( "y must be 5 - 18 = -13<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );