document.write( "Question 1018018: i need help sketching a graph that has two real zeros at -2 and 2 then another that has two imaginary zeros at -2i and 2i.i have no idea how to start it
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Algebra.Com's Answer #634186 by josgarithmetic(39632)\"\" \"About 
You can put this solution on YOUR website!
Not really enough information given. The two real zeros can be a parabola or quadratic function
\n" ); document.write( "and the simplest function can simply use those two zeros for the binomial roots.\r
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\n" ); document.write( "\n" ); document.write( "The example using the two imaginary zeros will not cross nor touch the x-axis, and because no
\n" ); document.write( "information is given to say anything about the leading coefficient, you do not have information
\n" ); document.write( "about vertex as max or as min. Pick either and as simple as possible.
\n" ); document.write( "\"y=%28x-2i%29%28x%2B2i%29\"
\n" ); document.write( "\"y=x%5E2-%282i%29%5E2\"
\n" ); document.write( "\"y=x%5E2-4i%5E2\"
\n" ); document.write( "\"y=x%5E2-4%2A%28-1%29\"
\n" ); document.write( "\"highlight%28y=x%5E2%2B4%29\"\r
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\n" ); document.write( "\n" ); document.write( "This as picked, opens upward, HAS NO REAL ZEROS, therefore has no x-axis intercepts, and has
\n" ); document.write( "a vertex minimum at (0,4). Same as the graph of y=x^2 but raised upward by 4 units.\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28300%2C300%2C-8%2C8%2C-2%2C14%2Cx%5E2%2B4%29\"
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