document.write( "Question 1018018: i need help sketching a graph that has two real zeros at -2 and 2 then another that has two imaginary zeros at -2i and 2i.i have no idea how to start it
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #634186 by josgarithmetic(39632) ![]() You can put this solution on YOUR website! Not really enough information given. The two real zeros can be a parabola or quadratic function \n" ); document.write( "and the simplest function can simply use those two zeros for the binomial roots.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The example using the two imaginary zeros will not cross nor touch the x-axis, and because no \n" ); document.write( "information is given to say anything about the leading coefficient, you do not have information \n" ); document.write( "about vertex as max or as min. Pick either and as simple as possible. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This as picked, opens upward, HAS NO REAL ZEROS, therefore has no x-axis intercepts, and has \n" ); document.write( "a vertex minimum at (0,4). Same as the graph of y=x^2 but raised upward by 4 units.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |