document.write( "Question 1018007: A chemist wants to mix three different solutions to create 100 milliliters of a solution that is 15% alcohol. Solution A is​ 10% alcohol, solution B is​ 15% alcohol, and solution C is​ 30% alcohol. The amount of solution A that is used must be three times the amount of solution B that is used. How many milliliters of each solution should the chemist​ combin \n" ); document.write( "
Algebra.Com's Answer #634181 by josgarithmetic(39628)\"\" \"About 
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document.write( "a   volume solution A   concentration 10%\r\n" );
document.write( "b   volume solution B   conc,  15%\r\n" );
document.write( "c   volume solution C   conc, 30%\r\n" );
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document.write( "a=3b\r\n" );
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document.write( "100 ml. of solution wanted, 15% concentration result.\r\n" );
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\n" ); document.write( "\n" ); document.write( "This is your starting system: \"system%28a%2Bb%2Bc=100%2C10a%2B15b%2B30c=100%2A15%2Ca=3b%29\"\r
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\n" ); document.write( "\n" ); document.write( "Immediately simplify the concentration equation.
\n" ); document.write( "\"2a%2B3b%2B6c=20%2A15\"
\n" ); document.write( "\"2a%2B3b%2B6c=300\"\r
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\n" ); document.write( "\n" ); document.write( "And substitute for a in the volume and simplified concentration equations.
\n" ); document.write( "\"system%283b%2Bb%2Bc=100%2C2%2A3b%2B3b%2B6c=300%29\"
\n" ); document.write( "\"system%284b%2Bc=100%2C9b%2B6c=300%29\"
\n" ); document.write( "and one more simplification...
\n" ); document.write( "\"highlight%28system%284b%2Bc=100%2C3b%2B2c=100%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "Not a big problem from here. You finish.
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