document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017821>Question 1017821</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An error of 2% was made in measuring the radius of a sphere. Find the approximate sorrespong percentage error the mesuring of irts volume.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #634112 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=634112\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> It will be a function of the cube.<BR>\n" );
document.write( "As an example, suppose the actual radius is 1, but the error makes it 0.98 or 1.02<BR>\n" );
document.write( "the cube of those two numbers differing from 1 will be the volume error, (0.94 to 1.06) or about 6%. </SPAN>\n" );
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