document.write( "Question 1017822: Sketch the curve y=x^3-9x^2+15x-7 indicationg clearly it point of intercetion with the axes and its turning points.
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Algebra.Com's Answer #634067 by Alan3354(69443)\"\" \"About 
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Sketch the curve y=x^3-9x^2+15x-7 indicationg clearly it point of intercetion with the axes and its turning points.
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\n" ); document.write( "Pick values for x and find y.
\n" ); document.write( "eg
\n" ); document.write( "x = 0, y = -7 --> (0,-7)
\n" ); document.write( "x = 1, y = 0 --> (1,0)
\n" ); document.write( "Plot as many points as you like, then draw a curve thru them.
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\n" ); document.write( "Use Excel to make a table if you have that.
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\n" ); document.write( "The intersection with the y-axis is at x = 0, shown above (0,-7)
\n" ); document.write( "One intersection with the x-axis is (1,0) shown above.
\n" ); document.write( "x^3-9x^2+15x-7 = (x-1)*(x-1)*(x-7)
\n" ); document.write( "--> intersections at x = 1, 1, 7
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\n" ); document.write( "The 1st derivative y' = 3x^2 - 18x + 15
\n" ); document.write( "--> x^2 - 6x + 5 = 0
\n" ); document.write( "(x-1)*(x-5) = 0
\n" ); document.write( "--> turning points at x = 1 and x = 5\r
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