document.write( "Question 1017834: (8x^3 + 343) / (8x+28) divided by (8x^3 - 28x + 98) / 16x
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Algebra.Com's Answer #634058 by rothauserc(4718)\"\" \"About 
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(8x^3 + 343) / (8x+28) divided by (8x^3 - 28x + 98) / 16x
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\n" ); document.write( "Note that (8x^3 + 343) is the sum of two cubes whose factorization is
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\n" ); document.write( "(2x+7)(4x^2 -14x +49) and therefore the first fraction is
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\n" ); document.write( "(2x+7)(4x^2 -14x +49) / 4(2x+7) = (4x^2 -14x +49) / 4
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\n" ); document.write( "The second fraction can be reduced
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\n" ); document.write( "(8x^3 - 28x +98) / 16x = (4x^3 -14x +49) / 8x
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\n" ); document.write( "Now invert the second fraction and multiply by the first
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\n" ); document.write( "((4x^2 -14x +49) / 4) * (8x / (4x^3 -14x +49))
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\n" ); document.write( "(8x^3 -28x^2 +98x) / (4x^3 -14x +49) \n" ); document.write( "
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