document.write( "Question 1017846: two numbers are in the ratio of 4:5. the value of the large number is 35 more than the smaller number, then the product of the numbers is ? \n" ); document.write( "
Algebra.Com's Answer #634049 by Theo(13342)![]() ![]() You can put this solution on YOUR website! let the numbers be x and y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ratio between x and y is x/y = 4/5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the value of the larger number is 35 more than the smaller number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "if the ratio of x/y = 4/5, then y must be the larger number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "how do you know that?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve the equation for x to get x = 4/5 * y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since the fraction is less than 1, x must be smaller than y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the problem states that the larger number is equal to 35 more than the smaller number.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this means that y = x + 35.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since y = x + 35, the ratio of x/y = 4/5 becomes x/(x+35) = 4/5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cross multiply to get 5x = 4 * (x+35)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 5x = 4x + 140\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract x from both sides of the equation to get 5x - 4x = 4x + 140 - 4x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get x = 140.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since y = x + 35, then y must be equal to 175.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you have x = 140 and y = 175.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ratio between x and y is 4/5, so you get x/y = 4/5 becomes 140/175 = 4/5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since 4 goes into 140 thirty five times, then divide numerator and denominator of 140/175 by 35 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(140/35) / (175/35) = 4/5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the ratio holds.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 140 and y = 175.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "multiply x and y together to get 140 * 175 = 24500.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the product of the numbers is 24,500.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |