document.write( "Question 1017803: log(18-2x)=1\r
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Algebra.Com's Answer #634007 by ikleyn(52834)\"\" \"About 
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document.write( "\"log%28%2818-2x%29%29\" = \"1\"  <----->  18 - 2x = 10   (I assume that the logarithm base is 10)  ----->  2x = 18 - 10 = 8  ---->  x = \"8%2F2\" = 4.\r\n" );
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document.write( "Answer.  x = 4.\r\n" );
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