document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1017702>Question 1017702</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate: negative x to the negative second power plus negative x to the second power multiplied by (x-m)    if -10-3x=2x and m+3=6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #633963 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=633963\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x^(-2)+-x^(-2)*(x-m)<BR>\n" );
document.write( "-10=5x<BR>\n" );
document.write( "x=-2<BR>\n" );
document.write( "m=3<BR>\n" );
document.write( "(x-m)=(-5)<BR>\n" );
document.write( "-x^(-2)+-x^(-2)*(x-m)<BR>\n" );
document.write( "2^(-2)+2^(-2)*-5\r<BR>\n" );
document.write( "\n" );
document.write( "(1/4)+(1/4)*-5<BR>\n" );
document.write( "multiplication first<BR>\n" );
document.write( "1/4+(-5/4)<BR>\n" );
document.write( "-1 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );