document.write( "Question 1017708: Kelly, a chemist, was asked to prepare 24 gallons of a solution that is 50% acidic by mixing a solution that is 20% acidic with another solution that is 70% acidic. How much of each solution should she use? \n" ); document.write( "
Algebra.Com's Answer #633951 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Kelly, a chemist, was asked to prepare 24 gallons of a solution that is 50% acidic by mixing a solution that is 20% acidic with another solution that is 70% acidic. How much of each solution should she use? \n" ); document.write( "---------- \n" ); document.write( "Equation:: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.20x + 0.70(24-x) = 0.50*24 \n" ); document.write( "------------------- \n" ); document.write( "20x + 70*24 - 70x = 50*24 \n" ); document.write( "-------- \n" ); document.write( "-50x = -20*24 \n" ); document.write( "-------- \n" ); document.write( "x = (2/5)*24 \n" ); document.write( "----- \n" ); document.write( "x = 48/5 = 9.6 gallons (amt. of 20% solution needed) \n" ); document.write( "24-x = 13.4 gallons (amt. of 70% solution needed) \n" ); document.write( "--------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------ \n" ); document.write( " |