document.write( "Question 1017708: Kelly, a chemist, was asked to prepare 24 gallons of a solution that is 50% acidic by mixing a solution that is 20% acidic with another solution that is 70% acidic. How much of each solution should she use? \n" ); document.write( "
Algebra.Com's Answer #633951 by stanbon(75887)\"\" \"About 
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Kelly, a chemist, was asked to prepare 24 gallons of a solution that is 50% acidic by mixing a solution that is 20% acidic with another solution that is 70% acidic. How much of each solution should she use?
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\n" ); document.write( "Equation::
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.20x + 0.70(24-x) = 0.50*24
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\n" ); document.write( "20x + 70*24 - 70x = 50*24
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\n" ); document.write( "-50x = -20*24
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\n" ); document.write( "x = (2/5)*24
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\n" ); document.write( "x = 48/5 = 9.6 gallons (amt. of 20% solution needed)
\n" ); document.write( "24-x = 13.4 gallons (amt. of 70% solution needed)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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